作业帮已知：如图,AE⊥AB,BC⊥AB,AE=AB,ED=AC 求证：ED⊥AC
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已知：如图,AE⊥AB,BC⊥AB,AE=AB,ED=AC 求证：ED⊥AC
已知：如图,AE⊥AB,BC⊥AB,AE=AB,ED=AC 求证：ED⊥AC
已知：如图,AE⊥AB,BC⊥AB,AE=AB,ED=AC 求证：ED⊥AC
因为AE⊥AB,BC⊥AB,所以角EAB=角B=90度.又因为AE=AB,ED=AC ,所以△AED全等于△ABC.所以∠CAB=∠E.又因为∠E+∠ADE=90°,所以∠CAB+∠ADE=90°,即ED⊥AC
已知,如图,AB⊥BC,AE⊥ED,AB=AE,
已知:如图,AB⊥BC,AE⊥ED,AB=AE,
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已知：如图,AE⊥AB,BC⊥AB,AE=AB,ED=AC.求证：ED⊥AC.
已知：如图,AE⊥AB,BC⊥AB,AE=AB,ED=AC 求证：ED⊥AC
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已知:如图,AB⊥BC,AE⊥ED,AB=AE∠ACD=∠ADC.求证:BC=ED请写过程,谢谢!
已知:如图,AB⊥BC,AE⊥AD,AB=AE,∠ACD=∠ADC.求证:BC=ED