MOV AX,9678H ADD AL,AH ah= cf= zf= sf= of= afMOV AX,9678H ADD AL,AHah= cf= zf= sf= of= af=

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MOV AX,9678H ADD AL,AH ah= cf= zf= sf= of= afMOV AX,9678H ADD AL,AHah= cf= zf= sf= of= af=

MOV AX,9678H ADD AL,AH ah= cf= zf= sf= of= afMOV AX,9678H ADD AL,AHah= cf= zf= sf= of= af=
MOV AX,9678H ADD AL,AH ah= cf= zf= sf= of= af
MOV AX,9678H ADD AL,AH
ah= cf= zf= sf= of= af=

MOV AX,9678H ADD AL,AH ah= cf= zf= sf= of= afMOV AX,9678H ADD AL,AHah= cf= zf= sf= of= af=
ah=96H ADD是加到AL上的SH不变
CF=1 高位有进位
ZF=0 运算结果不为零
SF=0 结果为正数
OF=1 结果>127
AF=0
不太确定

写出每条汇编指令执行后,相关寄存器中的值 mov ax,62627 AX= mov ah,31h AX= mov al,23h AX= add ax,axmov ax,62627 AX= mov ah,31h AX= mov al,23h AX= add ax,ax AX=mov bx,826ch AX=mov cx,ax AX=mov ax,bx A=add ax,bx A=mov al,bh A=add ah,ah mov ax,5634h add al,ah ;ax=?daa ; ax=? MOV AX,9678H ADD AL,AH ah= cf= zf= sf= of= afMOV AX,9678H ADD AL,AHah= cf= zf= sf= of= af= mov al,0fbh ; al=0fbh add al,07h ; al=02h 微机原理的题一.程序分析 1.MOV AX,80F0H MOV CL,10H SAR AX,CL ADD AX,80H 则有:(AX)=_______ (CL)= ________ CF=_________ 2.XOR AX,AX OR AX,0040H TEST AX,0040H 则有:(AX)=_______ ZF=________ 3.XOR AL,AL MOV CX,3 COUNT:ADD AL, 写出下面每条指令执行后,ZF.PF.SF.CF.OF等标志位的值sub al,al mov al,10h add al,90h mov al,80h add al,80h mov al,0fch add al,05h mov al,7dh add al,0bh 这句add al,80h 执行后cf等于1,of也等于1,还有这句add al,05h执行后cf等 MOV AX,2000H MOW DS,AX MOC CL,4 MOV SI,2000H MOV AL,[SI+1] SI是多少? MOV AX 4C9AH MOV BX 75BDA XCHG AH , AL ADD BX, AX MOV CH ,AH MOV CL,BL DEC CX 求AX?BX?AH?CH?CL?BL?解答过程详细一点MOV AX 4C9AH MOV BX 75BDA XCHG AH , AL ADD BX, AX MOV CH ,AH MOV CL,BL DEC CX 求AX?BX?A 分别指出下列指令中源操作数和目的操作数的寻址方式(1) MOV SI ,‘C’ (4) ADD CX ,DS:[10H](2) MOV [BX+3] ,AX (5) MOV DL ,[BP+DI](3) SUB [BX][SI] ,AL (6) MOV [BX] ,AX 汇编语言 al=13h mov buf[di],al mov ax.dw1[bx][si] mov汇编语言 al=13hmov buf[di],almov ax.dw1[bx][si]mov word ptr buf,ax 执行指令“MOV AX,1365H”和“XCHG AL,AH”后,AX= 跪地打滚求汇编语言高手!回答以下问题,说出对与错.并说明错误的地方.1)MOV BX,[BX][SI]2)ADC VARI,[BP][DI]3)SBB [BX][BP],AX4)PUSH 5678H5)SHL [BP][SI],CL6)ROR AX,27)NEG AX,BX8)LEA CS,AX9)MOV AL,BX10)ADD DS:200H,AX11)AND [BX][BP 关于汇编的一道题目我想知道具体解答过程DA1 DB ′01234′ DA2 DB 5 DUP(0) MOV SI,0 MOV CX,5 LOP:MOV AL,DA1〔SI〕 ADD AL,11H OR AL,01H MOV DA2〔SI〕,AL INC SI LOOP LOP试问:(1)程序段执行后,写出DA2各字节中的数 MOV AX,ES:[2000H] SUB AL,07H 有什么用?DATA SEGMENT NUM DB ,SUM DB DATA ENDSCODE SEGMENT ASSUME CS:CODE,DS:DATASTART:MOV AX,DATA MOV DS,AX MOV CX,2 LEA SI,NUMS0:MOV AH,01H INT 21H CMP AL,'9' JBE NEXT SUB AL,07H -->有什么作用?NEXT:SUB AL,30H -->有什么作用? 溢出标志和符号标志mov ax,7ff0hadd al,10h ;0f=?,sf=?add ah,1 ;0f=?,sf=?add ax,2 ;0f=?,sf=?经过上面运算后of和sf分别等于多少?他说连续执行下来的,不是每次加都先赋7ff0h的.还有.能不能说一下怎么来的吗? START DW 10H,20H,30H,40H,50H EE1 DW 3 ┇ MOV BX,OFFSET START ADD BX,EE1 MOV AX,[BX]求ax 判断对错,说明原因 微机原理 mov ip ,ax mov al ,300 mov [sp] ,ax mov ax,bx+di