求大神解决不定积分dy/dx=(1-y)^0.92

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求大神解决不定积分dy/dx=(1-y)^0.92

求大神解决不定积分dy/dx=(1-y)^0.92
求大神解决不定积分dy/dx=(1-y)^0.92

求大神解决不定积分dy/dx=(1-y)^0.92
dy/(1-y)^0.92=dx
(1-y)^(-0.92)dy=dx
积分
(1-y)^(1-0.92)/(1-0.92)=x+C'
(1-y)^0.08=0.08x+0.08C'=0.08x+C
y=1-(0.08x+C)^12.5