xy-1+x-y

来源：学生作业帮助网编辑：作业帮时间：2024/05/01 16:43:56

xy-1+x-y
xy-1+x-y

xy-1+x-y
xy-1+x-y
=XY+X-Y-1(加法交换律）
=（XY+X）－（Y＋1）
＝X（Y＋1）－(Y+1)（提取公因式X）
=(Y+1)(X-1)（提取公因式Y+1）
这样可以么?

原式=x-1+y(x-1)=（x-1）(y+1)

xy-1+x-y=(xy+x)-(1+y)=x(y+1)-(y+1)=(y+1)(x-1)
精锐长宁天山

xy-1+x-y
=(xy+x)-(1+y)
=x(y+1)-(y+1)
=(y+1)(x-1)

xy-1+x-y (xy+1)(x+1)(y+1)+xy (xy+1)(x+1)(y+1)+xy (xy+1)(x+1)(y+1)+xy .(x+y-2)(x+y-2xy)+(xy-1)^2 分解因式(xy+1)(x+y+xy+1)+xy 因式分解xy-x-y+1 xy+x+y+1因式分解 1-x-y+xy 因式分解因式分解:xy+x+y+1 xy-1+x-y因式分解 xy-x-y+1因式分解钻机XY-1 ,X,Y, 化简xy-1-x+y (x+y)(x+y+2xy)+(xy+1)(xy-1)(x+y)(x-y)+4(y-1) 证明:(y/x)+(x/y)+xy≥x+y+1 计算3xy[2xy-x(y-2)+x-1] {(x-y/x^2-2xy+y^2)-(xy+y^2/x^2-y^2)}*(xy/y-1)