lim n^2(k/n-1/n+1-1/n+2-.-1/n+k)(其中K是与N无关的常数)谢谢个路大侠lim n^2{(k/n)-(1/n+1)-(1/n+2)-....-(1/n+k)}(其中K是与N无关的常数)lim下有N-正无穷

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/12 18:18:14
lim n^2(k/n-1/n+1-1/n+2-.-1/n+k)(其中K是与N无关的常数)谢谢个路大侠lim n^2{(k/n)-(1/n+1)-(1/n+2)-....-(1/n+k)}(其中K是与N无关的常数)lim下有N-正无穷

lim n^2(k/n-1/n+1-1/n+2-.-1/n+k)(其中K是与N无关的常数)谢谢个路大侠lim n^2{(k/n)-(1/n+1)-(1/n+2)-....-(1/n+k)}(其中K是与N无关的常数)lim下有N-正无穷
lim n^2(k/n-1/n+1-1/n+2-.-1/n+k)(其中K是与N无关的常数)
谢谢个路大侠
lim n^2{(k/n)-(1/n+1)-(1/n+2)-....-(1/n+k)}(其中K是与N无关的常数)
lim下有N-正无穷

lim n^2(k/n-1/n+1-1/n+2-.-1/n+k)(其中K是与N无关的常数)谢谢个路大侠lim n^2{(k/n)-(1/n+1)-(1/n+2)-....-(1/n+k)}(其中K是与N无关的常数)lim下有N-正无穷
k/n-1/n+1-1/n+2-.-1/n+k=(1/n-1/(n+1))+...+(1/n-1/(n+k))
而(1/n-1/(n+i))*n^2=i/(1+i/n).当n趋于无穷时极限为i
所以原式=1+2+.+k=k(k+1)/2

1