作业帮sin(arccos1/2+arccos1/3)
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sin(arccos1/2+arccos1/3)
sin(arccos1/2+arccos1/3)
sin(arccos1/2+arccos1/3)
原式=sin(arccos1/2)cos(arccos1/3)+cos(arccos1/2)sin(arccos1/3)
=√3/2*1/3+1/2*2√2/3
=(√3+2√2)/6
sin(arcsin1/2+arccos1/3)
=sin（arcsin1/2）cos(arccos1/3)+cos(arcsin1/2)sin(arccos1/3)
=1/2*1/3+根号（1-(1/2)^2）*根号（1-（1/3)^2）
=1/6+（根号3）/2*2根号（2）/3
=1/6+(根号6)/3
=(1+2根号6）/6
化简的每一步都写
sin(arccos1/2+arccos1/3)
sin(arccos1/2)
sin(arcsin1/2+arccos1/3)?
arccos1+arcsin1+arccos(-1)=?
求值:sin(2arcsin1/3+arccos1/5)
sin(2arcsin1/3arccos1/5)
求值:arcsin√2/2+arccos1/2+arcsin√3/2+arccos√2/2=
计算：arcsin(-根号2/2)-arccos(-1/2)+arctan(-1)-arccos1
sin(arccos1/3)=?
sin(arccos1/4)=?
化简 sin(arccos1/2+arccos1/3)化简的每一步都写
1.若arccos(cosx)=x,则x的范围2.适合cosx=-1/3,x∈(-π,-π/2)的x值是A.arccos(-1/3) B.π-arccos1/3C.-arccos(-1/3) D.-arccos1/3
sin(arccos(2sin(a)))=
用弧度制表示下列各式的值arcsin1/2= arccos(-^2/2)= arccos1= arctan(-^3)=
sin(arccos1/3)如何计算,
arccos1/2等于?
求值:sin(arcsin1/5+arccos1/3)helphelphelp
求值sin(arcSIN1/3+arcCos1/3)