求证:(sin 2x /(1-cos 2x) )·(sin x /(1+sin x))=tan (π/4-x/2).

求证：tan x/2=sin x/(1+cos x) 求证：1-sin(x)=cos(x)*tan(x/2) 求证（cos^2 x-sin^2 x)(cos^4 x+sin^4 x)+1/4 sin 2x sin 4x=cos 2x 求证:sin^2/(sin-cos) - (sin+cos)/(tan^2 -1) =sin+cos 求证：(sin x+cos x)(1-tan x)=(2sin x)/(tan2x) 求证(3-sin^4 x-cos^4 x)/2cos^2 x=1+tan^2 x+sin^2 x 求证 cos^8(x)-sin^8(x)=cos2x【1-1/2sin^2（2x)】 求证sin^4x+cos^4x=1-2sin^2xcos^2x 求证:Sin^2 x / (sinx-cosx) - (sin x + cos x)/(ta求证:Sin^2 x / (sinx-cosx) - (sin x + cos x)/(tan^2-1) = sin x + cos x 求证 1+2sinxcosx/sin^2x-cos^2x=sin^2x-cos^2x/1-2sinxcosx 求证（cos^2x-sin^2x)(cos^4x+sin^4x）+1/4sin2xsin4x=cos2x 求证：1-cos^4x-sin^4x/1-cos^6x-sin^6x=2/3 求证:(sin 2x /(1-cos 2x) )·(sin x /(1+sin x))=tan (π/4-x/2). 求证sin^4x-cos^4x=sin^2x-cos^2x 三角等式求证：cos^6x+sin^6x=1-3sin^2x+3sin^4x 求证sin^2x+sin^2y-sin^2x*sin^2y+cos^2x*cos^2y=1 求证1+sin a+cos a+2sin acos a/1+sin a+cos a=sin a+cos a 求证:sin 2a/1+sin a+cos a=sin a+cos a-1急