化简sinπ/12-√3cosπ/12化简sinπ/12-√3cosπ/12
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化简sinπ/12-√3cosπ/12化简sinπ/12-√3cosπ/12
化简sinπ/12-√3cosπ/12
化简sinπ/12-√3cosπ/12
化简sinπ/12-√3cosπ/12化简sinπ/12-√3cosπ/12
sinπ/12-√3cosπ/12
=2*(1/2*sinπ/12-√3/2*cosπ/12)
=2*(cosπ/3*sinπ/12-sinπ/3*sinπ/12)
=2*sin(π/12-π/3)
=-2sinπ/4
=-√2
sinπ/12-√3cosπ/12=2(1/2sinπ/12-√3/2cosπ/12)=
2(sinπ/12cosπ/3-sinπ/3cosπ/12)=2sin(π/12-π/3)=2sin-π/4=-2*√2/2=-√2
sinπ/12-√3cosπ/12
=2(1/2*sinπ/12-√3/2*cosπ/12)
=2(sinπ/12cosπ/6-cosπ/12sinπ/6)
=2sin(π/12-π/6)
=2sin(-π/12)
=-2sinπ/12
sinπ/12-√3cosπ/12
=2(1/2*sinπ/12-√3/2cosπ/12)
=2sin(π/12-π/3)
=-2sinπ/4
=-根号2
化简sinπ/12-√3cosπ/12化简sinπ/12-√3cosπ/12
sinπ/12-√3cosπ/12的值
√3cosπ/12-sinπ/12=
若方程12x²+πx-12x=0的两的根分别是α,β,则cosαcosβ-√3sinαcosβ-√cosαsinβ-sinαsinβ=
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化简 cos (π/12)+√3sin(π/12)=
(sinπ/24)(cosπ/24)(cosπ/12)
(sinπ/24)(cosπ/24)(cosπ/12)
sinπ/12*cosπ/12=?
求值:sin(π/12)+cos(π/12)
sin(π/12)-cos(π/12)=
cos*π/12—sin*π/12
cosπ/12乘以sinπ/12
计算cosπ/12*sinπ/12
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