log(√2+1)(3+2√2)+log√3(√6+3√3)-log3(2+√3)=

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/10 19:41:48
log(√2+1)(3+2√2)+log√3(√6+3√3)-log3(2+√3)=

log(√2+1)(3+2√2)+log√3(√6+3√3)-log3(2+√3)=
log(√2+1)(3+2√2)+log√3(√6+3√3)-log3(2+√3)=

log(√2+1)(3+2√2)+log√3(√6+3√3)-log3(2+√3)=
原式=log(√2+1)[(√2+1)²]+log3[(√6+3√3)²÷(2+√3)]
=2log(√2+1)(√2+1)+log3[(33+12√2)÷(2+√3)]
=2+log3[(33+12√2)/(2+√3)]
你写错了