作业帮换元法解方程x/(x-1)+[3(x-1)/x]-2=0时,设x/(x-1)=y,方程可化为整式方程为?A.y²－2y＋3＝0 B.y²＋2y＋3＝0C.y²＋3y－2＝0 D.y＋3/y－2＝0
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/03 01:30:22
![换元法解方程x/(x-1)+[3(x-1)/x]-2=0时,设x/(x-1)=y,方程可化为整式方程为?A.y²－2y＋3＝0 B.y²＋2y＋3＝0C.y²＋3y－2＝0 D.y＋3/y－2＝0](/uploads/image/z/585425-65-5.jpg?t=%E6%8D%A2%E5%85%83%E6%B3%95%E8%A7%A3%E6%96%B9%E7%A8%8Bx%2F%28x-1%29%2B%5B3%28x-1%29%2Fx%5D-2%3D0%E6%97%B6%2C%E8%AE%BEx%2F%28x-1%29%3Dy%2C%E6%96%B9%E7%A8%8B%E5%8F%AF%E5%8C%96%E4%B8%BA%E6%95%B4%E5%BC%8F%E6%96%B9%E7%A8%8B%E4%B8%BA%3FA.y%26%23178%3B%EF%BC%8D2y%EF%BC%8B3%EF%BC%9D0+B.y%26%23178%3B%EF%BC%8B2y%EF%BC%8B3%EF%BC%9D0C.y%26%23178%3B%EF%BC%8B3y%EF%BC%8D2%EF%BC%9D0+D.y%EF%BC%8B3%2Fy%EF%BC%8D2%EF%BC%9D0)
换元法解方程x/(x-1)+[3(x-1)/x]-2=0时,设x/(x-1)=y,方程可化为整式方程为?A.y²－2y＋3＝0 B.y²＋2y＋3＝0C.y²＋3y－2＝0 D.y＋3/y－2＝0
换元法解方程x/(x-1)+[3(x-1)/x]-2=0时,设x/(x-1)=y,方程可化为整式方程为?
A.y²－2y＋3＝0 B.y²＋2y＋3＝0
C.y²＋3y－2＝0 D.y＋3/y－2＝0
换元法解方程x/(x-1)+[3(x-1)/x]-2=0时,设x/(x-1)=y,方程可化为整式方程为?A.y²－2y＋3＝0 B.y²＋2y＋3＝0C.y²＋3y－2＝0 D.y＋3/y－2＝0
选D y+3/y-2=0