(x-y)²-(y-z)²=?x²+5x-6=

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(x-y)²-(y-z)²=?x²+5x-6=

(x-y)²-(y-z)²=?x²+5x-6=
(x-y)²-(y-z)²=?
x²+5x-6=

(x-y)²-(y-z)²=?x²+5x-6=
(x-y)²-(y-z)²
=[(x-y)+(y-z)][(x-y)-(y-z)]
=(x-z)(x-2y+z)

(x-y)²-(y-z)²=(x-y-y+z)(x-y+y-z)=(x-2y+z)(x-z)

(x-y)²-(y-z)²
=[(x-y)-(y-z)][(x-y)+(y-z)]
=(x-y-y-z)(x-y+y-z)
=(x-2y-z)(x-z)


x²+5x-6
=(x+6)(x-1)

原式子=(x-y+y-z)(x-y-y+z)=(x-z)(x+z)