若(a^m+1b^n+2)·(a^2n-1b^2m)=a^5b^5写错了,是若(a^m+1b^n+2)(a^2n-1b^2n)=a^5b^5

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若(a^m+1b^n+2)·(a^2n-1b^2m)=a^5b^5写错了,是若(a^m+1b^n+2)(a^2n-1b^2n)=a^5b^5

若(a^m+1b^n+2)·(a^2n-1b^2m)=a^5b^5写错了,是若(a^m+1b^n+2)(a^2n-1b^2n)=a^5b^5
若(a^m+1b^n+2)·(a^2n-1b^2m)=a^5b^5
写错了,是若(a^m+1b^n+2)(a^2n-1b^2n)=a^5b^5

若(a^m+1b^n+2)·(a^2n-1b^2m)=a^5b^5写错了,是若(a^m+1b^n+2)(a^2n-1b^2n)=a^5b^5
m+1+2n-1=5
n+2+2m=5
解得n=7/3,m=1/3

答:
(a^m+1b^n+2)(a^2n-1b^2n)=a^5b^5
m+2n-1=5
n+2+2n=5
所以:
m+2n=6
3n=3
解得:m=4,n=1
修改前的
[a^(m+1)b^(n+2)]·[a^(2n-1)b^(2m)]=(a^5)b^5
[a^(m+1+2n-1)]*[b^(n+2+2m)]=(a^5...

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答:
(a^m+1b^n+2)(a^2n-1b^2n)=a^5b^5
m+2n-1=5
n+2+2n=5
所以:
m+2n=6
3n=3
解得:m=4,n=1
修改前的
[a^(m+1)b^(n+2)]·[a^(2n-1)b^(2m)]=(a^5)b^5
[a^(m+1+2n-1)]*[b^(n+2+2m)]=(a^5)b^5
[a^(m+2n)]*b^(2m+n+2)=(a^5)b^5
所以:
m+2n=5
2m+n+2=5
解得:m=1/3,n=7/3

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