数列an ,a1=1,当n>=2时,an=（根号sn+根号sn-1）/2,证明根号sn是等差数列,求an

数列an满足a1=1,当n≥2时an²-(n+2)*an-1*an+2*n*an-1²=0 求通项公式 数列〔an〕满足an+1+an=4n-3,当a1=2时,求数列〔an〕前n项和 数列{an}中,a1=1,当n>1时,2Sn^2=2anSn-an,求通项an 数列{an}中,a1=1,当n>1时2Sn²=2anSn-an,求通项an 已知数列｛an｝满足an+1+an=4n-3 当a1=2时,求Sn 数列{An}满足a1=1/2,a1+a2+..+an=n方an,求an 已知数列an中满足a1=1且当n.=2时,2an*a*(n-1)+an-a(n-1)=0,求通项公式an 已知数列{an},其中a1=10,且当n≥2时,an=5an-1/6an-1+5,求数列{an}的通项公式已知数列{an},其中a1=10,且当n≥2时,an=(5an-1)/(6an-1)+5,求数列{an}的通项公 在数列{an}中,已知an+1=an+n,当an+1=2009时,求|a1|的最小值 如果数列{an}满足a1=4,an+1=an^2/2an-2,求当n>=2时,恒有an 设a1=5,当n≥2时an+an-1=7/(an-an-1)+6,求数列(an)的通项公式 数列证明题一题设数列{An}满足：A1=1,且当n∈N*时,An^3+An^2×[1－A(n+1)]+1=A(n+1）求证：数列{An}是递增数列. 数列{an}中,a1=1,当n>=2时,Sn=n2an (n的平方*an),求通项an.a1=1不是=1/2. 数列{an}中,a1=1,当n>=2时,Sn=n2an (n的平方*an),求通项an.a1=1不是=1/2. 已知数列｛an},a1=3,当n大于等于2时,an-1+an=4n,求an的通项公式. 已知数列{an} 满足a1=1/5,且当n>1,n∈N+时,an—1/an=2an—1+1/1—2an(1)求证：数列{1/an} 为等差数列； 数列{an}满足a1=1 an+1=2n+1an/an+2n 数列｛an},a1=1,an+1=2an-n^2+3n,求｛an｝.