化简[2x/(x2-4)-1/(x-2)]·(x+2)/(x-1)

来源：学生作业帮助网 编辑：作业帮 时间：2024/05/09 05:34:49
化简[2x/(x2-4)-1/(x-2)]·(x+2)/(x-1)

化简[2x/(x2-4)-1/(x-2)]·(x+2)/(x-1)
化简[2x/(x2-4)-1/(x-2)]·(x+2)/(x-1)

化简[2x/(x2-4)-1/(x-2)]·(x+2)/(x-1)
[2x/(x2-4)-1/(x-2)]·(x+2)/(x-1)
=[2x/(x+2)(x-2)-1/(x-2)]*(x+2)/(x-1)
=(2x-x-2)/(x+2)(x-2)*(x+2)/(x-1)
=1/(x+2)*(x+2)/(x-1)
=1/(x-1)

1/（x-2）分子分母同时乘以（x+2）然后得[2x/x2-4-1/(x-2)}=(x-2)/x2-4=1/(x+2）
然后乘以x+2再除以x-1等于1/（x-1)

[2x/(x2-4)-1/(x-2)]·(x+2)/(x-1)
={2x/[(x+2)(x-2)]-1/(x-2)}·(x+2)/(x-1)
={[2x-(x+2)]/[(x+2)(x-2)]}·(x+2)/(x-1)
={(x-2)/[(x+2)(x-2)]}·(x+2)/(x-1)
=[1/(x+2)]·(x+2)/(x-1)
=1/(x-1)

后面那框框的符号是什么？
[2x/(x2-4)-1/(x-2)]·(x+2)/(x-1)
=[x/(x-2)-1/(x-2)]·(x+2)/(x-1)
=[(x-1)/(x-2)]·(x+2)/(x-1)
=(x-2)/(x+2)

化简x/x2+x除以x2+x-2/x2-1+x+1/x+2 通分 3x/x2-2x,2x+1/4-x2,3/2x2+4x 3/x2 -3x+2-1/x-2=1/x2 -x+4/x2 -2x 化简x-1分之x+1-x2-1分之x2-2x÷x2-x-2/x2+2x+1 化简 √(16-8x+x2)-√(x2-2x+1)(1＜x＜4) 计算:x2-5x+6/x2-4x+3 + x2-4x+3/x2-2x+1 + x2-3x-4/1-x2 因式分解 (x2+2x)2+2x2+4x+1 证明:根号(x2+2x+4)-根号(x2-x+1) 化简1/x2-3x+2 +1/x2-x +1/x2+x +1/x2+3x+2 (x+1)(x2-x+1)+(x-2)(x2+2x+4),其中x=-3/2 化简：根号（x2+6x+9）+根号（x2-2x+1）-根号（x2-4x+4） （x+2)(x2-2x+4)+（x-1)(x2+x+1),其中x=-三分之二 化简x3-x2/x2-x+x2-4x+4/x-2 (X2-X)2+(X2+3X+2)2-4(X2+X+1)2因式分解 分解因式:4(3x2-x-1)(x2+2x-3)-(4x2+x-4)2 先化简,再求值：（4x2-3x)-2（x2+2x-1)-（x2+x-1) x2+3x+9/x2-27+6x/9x-x2-x-1/6+2x 化简 化简x2+3x+9/x2-27+6x/9x-x2-x-1/6+2x