5[x^2-x]=3[x^2+x][2x-3]^2=4[2x+3]

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5[x^2-x]=3[x^2+x][2x-3]^2=4[2x+3]

5[x^2-x]=3[x^2+x][2x-3]^2=4[2x+3]
5[x^2-x]=3[x^2+x]
[2x-3]^2=4[2x+3]

5[x^2-x]=3[x^2+x][2x-3]^2=4[2x+3]

5（x^2-5x）=3x^2-3x=0
即2x^2-8x=0
解得x=0或4
(2x-3)^2=9(2x+3)^2
(2x-3)^2=[3(2x+3)]^2
2x-3=±3(2x+3)
x1=-4 x2=-3/4

第一道 x1=0，x2=4
第二道 X1=（5+2*sqrt（7））/2 X2=（5-2*sqrt（7））/2

 

错了，第一个是4或0

1。 5x^2_5x=3x^2+3x.
2x^2=8x
2. 4x^2+9-12x=8x+12
4x^2-20x=3
把1带入。
X=- 3/4

5[x^2-x]=3[x^2+x]
x^2-2x=0
x=0 x=2
[2x-3]^2=4[2x+3]
4x^2-20x-3=0
x=20±8√7/8
x=5±2√7/2

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