f(n)=(1/n+1)+(1/n+2)+.+(1/3n+1),则f(k+1)=

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f(n)=(1/n+1)+(1/n+2)+.+(1/3n+1),则f(k+1)=

f(n)=(1/n+1)+(1/n+2)+.+(1/3n+1),则f(k+1)=
f(n)=(1/n+1)+(1/n+2)+.+(1/3n+1),则f(k+1)=

f(n)=(1/n+1)+(1/n+2)+.+(1/3n+1),则f(k+1)=
令k+1=n,带入原式,
f(k+1)=(1/k+2)+(1/k+3)+.+(1/3k+4)

设f(n)=(1/n+1) +(1/n+2) +…+(1/3n) 则f(k+1)-f(k)=?? (1/3n+3)+(1/3n+2)+(1/3n+1)-1/n+1

这个式子有问题啊。。
f(n)=(1/n+1)+(1/n+2)+....+(1/3n+1),
其中“...”省略的是什么呢?
你是不是打错了啊?