limx→1 1/(x-1)-2/(x^3-1)感觉有问题,

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limx→1 1/(x-1)-2/(x^3-1)感觉有问题,
limx→1 1/(x-1)-2/(x^3-1)
感觉有问题,

limx→1 1/(x-1)-2/(x^3-1)感觉有问题,
lim(x→1)[1/(x-1)-2/(x^3-1)]
=lim(x→1)[(x^2+x+1)/(x-1)(x^2+x+1)-2/(x^3-1)]
=lim(x→1)(x^2+x+1-2)/(x-1)(x^2+x+1)
=lim(x→1)(x^2+x-1)/(x-1)(x^2+x+1)
=1/0
=∞
会不会数据设置不合理,这样的话极限其实是不存在的,左极限和右极限会不一样,一个是正无穷,一个是负无穷
如果不懂,祝学习愉快!

lim(x→1) ( 1/(x-1)-3/(x^3-1) )
=lim(x→1) (x^2+x-2)/(x^3-1)
=lim(x→1) (x+2)(x-1)/[(x-1)(x^2+x+1)]
=lim(x→1) (x+2)/(x^2+x+1)
=1

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